Equivalent weight of NaOH = 40gm
Normality = Weight of the solute/Gram equivalent weight of sloute
N = 20/40 gm
= 0.5 gm
Normality for 100 ml sloution = 0.5/100/1000 (1000ml = 1 litre)(100ml = 100/1000)
= 0.5 x 1000/100
= 5N
