Let us denote the concentration of the 95% alcohol solution by A, and the concentration of the 70% alcohol solution by B. We can then construct a table like this:
Solution | % concentration | Quantity (ml) |
---|---|---|
A | 95 | x |
B | 70 | 300-x |
Mixture | 300 |
We want to find the value of x, which is the quantity of the 95% alcohol solution required to prepare the 300 ml of 70% alcohol solution.
To solve for x, we use the following formula:
(x * (95-70)) / (70-95) = (300-x)
Simplifying this equation, we get:
x = (300 * (70-95)) / (95-70)
x = 138.46 ml (rounded to two decimal places)
Therefore, we need 138.46 ml of the 95% alcohol solution to prepare 300 ml of 70% alcohol solution by alligation method.