Calculate the volume of 95% alcohol required to prepare 300 ml of 70% alcohol by alligation method.

Bright Pharma
0



 To use the alligation method to solve this problem, we need to understand that it involves mixing two solutions with different concentrations to get a solution with a desired concentration.

Let us denote the concentration of the 95% alcohol solution by A, and the concentration of the 70% alcohol solution by B. We can then construct a table like this:

Solution% concentrationQuantity (ml)
A95x
B70300-x
Mixture300

We want to find the value of x, which is the quantity of the 95% alcohol solution required to prepare the 300 ml of 70% alcohol solution.

To solve for x, we use the following formula:

(x * (95-70)) / (70-95) = (300-x)

Simplifying this equation, we get:

x = (300 * (70-95)) / (95-70)

x = 138.46 ml (rounded to two decimal places)

Therefore, we need 138.46 ml of the 95% alcohol solution to prepare 300 ml of 70% alcohol solution by alligation method.

Post a Comment

0 Comments
* Please Don't Spam Here. All the Comments are Reviewed by Admin.
Post a Comment (0)
Our website uses cookies to enhance your experience. Learn More
Accept !